Maximum Power Transfer Calculator

Evaluates a known Thevenin source against an entered resistive load and separates matched-load power from efficiency and equipment limits.

Inputs
Result

Formulas

  • \(R_{\mathrm{L,opt}} = R_{\mathrm{th}}\)
  • \(P_{\mathrm{max}} = \frac{V_{\mathrm{th}}^2}{4R_{\mathrm{th}}}\)
  • \(I_{\mathrm{L}} = \frac{V_{\mathrm{th}}}{R_{\mathrm{th}} + R_{\mathrm{L}}}\)
  • \(P_{\mathrm{L}} = I_{\mathrm{L}}^2 R_{\mathrm{L}}\)
  • \(\eta_{\mathrm{L}} = \frac{P_{\mathrm{L}}}{P_{\mathrm{source}}}\times 100\)

The Maximum Power Transfer Calculator determines the load resistance that receives the greatest possible power from a known ideal DC Thevenin source. Its primary result is Optimal load resistance: the load resistance that equals the source’s internal or Thevenin resistance.

This calculation is used after the source has already been reduced to a Thevenin equivalent. It helps evaluate source loading, compare an intended resistance with the matched condition, and quantify the resulting power, current, and efficiency. Typical applications include low-power DC circuits, test networks, sensor interfaces, resistive loads, and source-characterization work where extracting the highest available load power is the objective.

It is not an AC impedance-matching calculation, a branch-circuit sizing method, or an equipment-approval determination.

Thevenin Source and Load Resistance

An ideal Thevenin DC source consists of:

  • Thevenin voltage, the open-circuit equivalent source voltage
  • Source resistance, the resistance in series with that ideal voltage source
  • Entered load resistance, the actual load resistance being evaluated

The source resistance produces voltage drop whenever load current flows. A smaller load resistance draws more current but loses more voltage inside the source resistance. A larger load resistance preserves more load voltage but draws less current. Maximum load power occurs at the balance point between those two conditions.

For a DC source:

\(\displaystyle R_L = R_S\)

Where:

  • \(R_L\) = load resistance
  • \(R_S\) = source resistance

The calculator reports this value as Optimal load resistance.

Power-Transfer Calculation

With Thevenin voltage \(V_{TH}\), source resistance \(R_S\), and load resistance \(R_L\), the entered-load current is:

\(\displaystyle I_L = \frac{V_{TH}}{R_S + R_L}\)

The power delivered to the entered load is:

\(\displaystyle P_L = I_L^2R_L\)

Equivalent form:

\(\displaystyle P_L = \frac{V_{TH}^2R_L}{(R_S + R_L)^2}\)

At maximum power transfer, the load equals the source resistance:

\(\displaystyle R_L = R_S\)

The maximum available load power is therefore:

\(\displaystyle P_{MAX} = \frac{V_{TH}^2}{4R_S}\)

At this matched-resistance condition, the load voltage is one-half of the Thevenin voltage, and the source resistance dissipates the same power as the load. The resulting ideal source-to-load efficiency is:

\(\displaystyle \eta = \frac{R_L}{R_S + R_L} \times 100\%\)

When \(R_L = R_S\):

[ \eta = 50% ]

Maximum power transfer and maximum efficiency are different operating objectives. A load resistance greater than the source resistance will generally receive less power, but it will operate at higher efficiency because a smaller share of source power is dissipated in the source resistance.

Input and Result Definitions

Calculator fieldElectrical meaning
Thevenin voltageThe known equivalent DC source voltage, expressed in V
Source resistanceThe source or Thevenin resistance in series with the equivalent voltage source, expressed in ohm
Entered load resistanceThe load resistance being checked against the matched condition, expressed in ohm
Optimal load resistanceThe resistance that produces maximum load power; equal to Source resistance
Maximum load powerThe highest power available to a resistive load under the ideal DC Thevenin model
Entered-load powerPower dissipated by the specific Entered load resistance
Entered-load currentCurrent through the series combination of Source resistance and Entered load resistance
Entered-load efficiencyPercentage of source power delivered to the entered load rather than dissipated in Source resistance

Calculation Example

Given the following source model:

InputValue
Thevenin voltage12 V
Source resistance4 ohm
Entered load resistance4 ohm

The matched load resistance is:

\(\displaystyle R_L = R_S = 4\ \text{ohm}\)

So the calculator returns:

\(\displaystyle \text{Optimal load resistance} = 4\ \text{ohm}\)

The maximum load power is:

\(\displaystyle P_{MAX} = \frac{12^2}{4 \times 4}\)

\(\displaystyle P_{MAX} = 9\ \text{W}\)

For the entered 4-ohm load, circuit current is:

\(\displaystyle I_L = \frac{12}{4+4}\)

\(Entered-load current = 1.5\ \text{A}\)

Entered-load power is:

\(\displaystyle P_L = (1.5)^2 \times 4\)

\(Entered-load power = 9\ \text{W}\)

The source resistance also dissipates 9 W. Total source output is 18 W, with half delivered to the load:

(Entered-load efficiency = 50%)

The result set is therefore:

ResultValue
Optimal load resistance4 ohm
Maximum load power9 W
Entered-load power9 W
Entered-load current1.5 A
Entered-load efficiency50%

Practical Electrical Limits

The calculation assumes a linear, ideal DC Thevenin source with a fixed Thevenin voltage and fixed Source resistance. Actual batteries, power supplies, photovoltaic sources, generators, electronic converters, and controlled power systems may not maintain that model across their operating range.

Use the result to evaluate resistive source loading only. Verify the actual component power rating, thermal conditions, source current capability, voltage tolerance, protection behavior, conductor ampacity, terminal ratings, and voltage-drop conditions separately where those factors apply.

The maximum-power condition intentionally dissipates half of the generated power in the source resistance. It is appropriate when available load power is the design target, not when battery life, thermal performance, or overall DC power efficiency is the controlling requirement.

FAQs

What load receives maximum power?

For the ideal resistive DC model, the load resistance equals the source or Thevenin resistance.

Does maximum power mean maximum efficiency?

No. At the matched condition in this ideal model, efficiency is 50 percent. Maximum efficiency and maximum delivered power are different goals.

Does this solve AC impedance matching?

No. AC matching can require complex-conjugate impedance and a different model.