Motor Reflected Inertia Calculator
Combine multiple load-inertia rows before an acceleration, braking, or drive-sizing review.
- Entered load inertia total
- kg*m^2
- Linear equivalent inertia total
- kg*m^2
- Combined load inertia
- kg*m^2
- Reflected load inertia
- kg*m^2
- Motor-side total inertia
- kg*m^2
- Inertia ratio
- x
- Speed ratio used
- x
- Counted load rows
- rows
Calculation details
- Calculation basis
- Ratio boundary
- Selection boundary
Recent results
Formulas
- \(J_{\mathrm{linear}} = m \times r^2\)
- \(J_{\mathrm{load}} = J_{\mathrm{entered}} + J_{\mathrm{linear}}\)
- \(J_{\mathrm{reflected}} = \frac{J_{\mathrm{load}}}{N^2}\)
- \(J_{\mathrm{motor\ side}} = J_{\mathrm{rotor}} + J_{\mathrm{coupling}} + J_{\mathrm{reflected}}\)
- \(\mathrm{Inertia\ ratio} = \frac{J_{\mathrm{motor\ side}}}{J_{\mathrm{rotor}}}\)
A motor reflected inertia calculator converts the inertia of driven rollers, pulleys, rotating equipment, and linear loads into an equivalent value at the motor shaft. The primary result is Motor-side total inertia, the total inertia the motor must accelerate and decelerate after the speed ratio is applied.
Motor-side inertia is used during motor, gearbox, servo drive, VFD, and motion-system review. It affects acceleration torque, deceleration torque, stopping performance, regenerative braking requirements, and the motor’s ability to control speed without excessive current, overshoot, or mechanical stress. It is not a conductor ampacity, branch-circuit, feeder, raceway fill, or voltage-drop calculation; electrical supply conductors and overcurrent protection must be evaluated separately from the mechanical load reflected to the motor shaft.
Motor-Side Inertia
Every rotating system resists a change in speed. The motor must accelerate:
- Its own rotor.
- Any coupling, shaft, or adapter directly connected to the motor.
- The driven load, reduced or increased by the speed ratio between the motor and load.
The calculator reports these values:
| Result | Electrical and mechanical meaning |
|---|---|
| Entered load inertia total | Sum of all values entered directly in Entered load inertia (kg*m^2) |
| Linear equivalent inertia total | Sum of inertia calculated from Mass (kg) and Radius (m) for applicable load rows |
| Combined load inertia | Total load inertia before it is reflected through the speed ratio |
| Reflected load inertia | Combined load inertia expressed at the motor shaft |
| Motor-side total inertia | Motor rotor inertia plus motor-side coupling inertia plus reflected load inertia |
| Counted load rows | Number of load rows included in the calculation |
A speed reducer can substantially reduce the inertia seen by the motor. Conversely, a speed increaser can make the motor see a larger equivalent inertia. The relationship depends on the square of the speed ratio, not the ratio alone.
Required Entries
Enter Motor rotor inertia (kg*m^2) as the inertia of the selected motor rotor. This establishes the motor-side comparison base used for drive sizing and inertia-ratio review.
Enter Speed ratio (x) as:
\(\displaystyle \text{Speed ratio} = \frac{\text{Motor speed}}{\text{Load speed}}\)
A value of 2 means the motor turns twice as fast as the load. Gearbox catalogs and mechanical drawings sometimes state the inverse ratio, such as load speed divided by motor speed. Convert that convention before entering the value.
Enter Coupling inertia (kg*m^2) for direct-coupled components that remain on the motor side of the speed ratio, including a coupling, motor-side shaft extension, or adapter. This value is added directly to motor-side total inertia and is not divided by the speed ratio.
Each Load rows entry represents one driven element. Use Load label to identify the component, such as a roller, pulley, turntable, or linear carriage.
A load row can be entered by either method:
| Load-row method | Fields used | Calculation behavior |
|---|---|---|
| Known inertia | Entered load inertia (kg*m^2) | Adds the entered inertia directly to the load total |
| Mass-radius equivalent | Mass (kg) and Radius (m) | Calculates an equivalent inertia using \(m r^2\) |
For a mass-radius row, Radius (m) is the effective radius used to convert the moving mass into an equivalent rotating inertia. The selected radius must represent the actual mechanical relationship at the rotating element being evaluated.
Reflected-Inertia Formula
For each mass-radius load row:
\(\displaystyle J_{\text{row}} = m r^2\)
Where:
- \(J_{\text{row}}\) = equivalent inertia of the load row in kg·m²
- (m) =
Mass (kg) - (r) =
Radius (m)
The calculator combines directly entered and mass-radius inertia values:
\(\displaystyle J_{\text{combined load}} = J_{\text{entered load total}} + J_{\text{linear equivalent total}}\)
The load is then reflected to the motor shaft through the entered speed ratio:
\(\displaystyle \mathbf{J_{\text{reflected load}} = \frac{J_{\text{combined load}}}{(\text{Speed ratio})^2}}\)
Finally, the calculator determines the full inertia at the motor side:
\(\displaystyle \mathbf{J_{\text{motor-side total}} = J_{\text{motor rotor}} + J_{\text{coupling}} + J_{\text{reflected load}}}\)
The squared speed-ratio term is critical. With a 2:1 motor-to-load speed ratio, the motor sees one-quarter of the load-side inertia. With a 4:1 ratio, the motor sees one-sixteenth.
Calculation Example
Use the following entries:
| Field | Value |
|---|---|
Motor rotor inertia (kg*m^2) | 1 |
Speed ratio (x) | 2 |
Coupling inertia (kg*m^2) | 0 |
Row 1 Load label | Roller load |
Row 1 Entered load inertia (kg*m^2) | 4 |
Row 2 Load label | Linear carriage |
Row 2 Mass (kg) | 1 |
Row 2 Radius (m) | 2 |
The Roller load contributes 4 kg·m² directly.
For the Linear carriage row:
\(\displaystyle J = 1 \times 2^2 = 4\ \text{kg·m}^2\)
The load-side total is:
\(\displaystyle J_{\text{combined load}} = 4 + 4 = 8\ \text{kg·m}^2\)
With Speed ratio (x) equal to 2:
\(\displaystyle J_{\text{reflected load}} = \frac{8}{2^2} = 2\ \text{kg·m}^2\)
With 1 kg·m² of motor rotor inertia and no coupling inertia:
\(\displaystyle J_{\text{motor-side total}} = 1 + 0 + 2 = \mathbf{3\ \text{kg·m}^2}\)
The resulting calculator values are:
- Entered load inertia total: 4 kg·m²
- Linear equivalent inertia total: 4 kg·m²
- Combined load inertia: 8 kg·m²
- Reflected load inertia: 2 kg·m²
- Motor-side total inertia: 3 kg·m²
- Counted load rows: 2 rows
Motor and Drive Review
The calculated Motor-side total inertia is used with the required speed change and acceleration time to determine the inertia-related torque demand:
(T = J\alpha)
Where (T) is torque, (J) is the motor-side total inertia, and \(\alpha\) is angular acceleration. A complete motor calculation also includes friction, process load, gravity or overhauling load where applicable, gearbox efficiency, duty cycle, and required acceleration and deceleration time.
For a servo system, compare the final inertia ratio and torque demand with the motor and drive manufacturer’s published limits. For an induction motor or VFD application, use the result to evaluate acceleration capability, starting or ramp current, and whether the driven equipment can reach speed within the required time. Deceleration review may also require evaluation of regenerative energy, braking resistors, braking units, or mechanical braking.
The motor branch circuit remains a separate electrical design task. Motor full-load current, conductor ampacity, AWG or kcmil conductor selection, terminal temperature rating, overcurrent protection, disconnecting means, voltage drop, and equipment grounding must be selected from the applicable equipment data and governing code requirements, subject to AHJ enforcement.
Field Limits
The calculation assumes the entered values accurately represent the mechanical system and that the speed ratio is constant. Confirm the following before using the result for final equipment selection:
- Verify whether the speed ratio is motor speed divided by load speed; reverse-ratio entry produces a squared error in reflected inertia.
- Include every significant rotating or translated load, including rollers, drums, belts where applicable, pulleys, shafts, couplings, and driven equipment.
- Do not duplicate a component by entering both its known inertia and a mass-radius equivalent for the same physical item.
- Use manufacturer data or a mechanical-engineering calculation where load geometry is complex, mass distribution is nonuniform, belt compliance is significant, or acceleration includes changing radius or changing mass.
- Evaluate backlash, torsional compliance, gearbox efficiency, friction, external process torque, and braking energy separately; they are not represented by inertia alone.
- Verify motor, gearbox, coupling, driven-equipment, and drive ratings against the actual acceleration profile and operating duty.
FAQs
Why keep each load row separate?
Separate rows preserve the original equipment source and make it easier to trace the result back to a specific roller, carriage, or other driven element.
What speed ratio should I enter?
Enter motor speed divided by load speed. If your source uses the inverse ratio, convert it before using the page.
Does this page choose a motor or drive?
No. It only reflects load inertia to the motor side. Motor, drive, brake, and protection review still need separate engineering and manufacturer checks.