Voltage Sag Calculator
Estimates voltage sag and remaining voltage from system voltage, available fault current, and a load-current step for initial power-quality review.
- Estimated source impedance
- ohm
- Estimated voltage sag
- V
- Estimated sag
- %
- Remaining voltage
- V
- Remaining voltage
- %
- Phase multiplier
- x
Calculation details
- Calculation basis
- Selection boundary
Recent results
Formulas
- \(m = 1\ \text{for single-phase};\quad m = \sqrt{3}\ \text{for balanced three-phase}\)
- \(Z_{\mathrm{source}} = \frac{V_{\mathrm{system}}}{m I_{\mathrm{fault}}}\)
- \(V_{\mathrm{sag}} = m I_{\mathrm{step}} Z_{\mathrm{source}}\)
- \(\text{Sag (\%)} = 100 \times \frac{V_{\mathrm{sag}}}{V_{\mathrm{system}}}\)
- \(V_{\mathrm{remaining}} = V_{\mathrm{system}} - V_{\mathrm{sag}}\)
- \(\text{Remaining voltage (\%)} = 100 \times \frac{V_{\mathrm{remaining}}}{V_{\mathrm{system}}}\)
Electrical Purpose
A sudden load step—motor starting, welder firing, large contactor closing—draws a current spike against the source impedance of the supply. That current spike produces a momentary drop in terminal voltage, commonly called voltage sag or voltage dip. The Voltage Sag Calculator converts two field-measurable quantities, available fault current and a load-current step, into an estimated sag in volts and percent, using the source impedance implied by the fault current.
This is not a voltage-drop-over-distance calculation. Voltage drop from conductor resistance is a steady-state IR loss along a known conductor length; voltage sag is a transient dip driven by source impedance reacting to a current step. The two concepts use different inputs and answer different questions, but both are checked when a load causes flicker, nuisance tripping, or equipment reset at start-up.
Inputs
- System voltage — the voltage basis for the sag estimate, in volts. Enter line-to-line voltage for three-phase estimates (480 V in the example).
- Available fault current — the available fault current at the point of interest, in amperes, used as a source-strength screening proxy (10,000 A in the example). Higher fault current implies a stiffer source and lower impedance.
- Load-current step — the sudden load or motor-starting current step being screened, in amperes (800 A in the example).
- Phase count — Single-phase or Three-phase, selected to set the impedance and sag formula used for the display.
Outputs
- Estimated source impedance — the implied source impedance in ohms, derived from system voltage and available fault current.
- Estimated voltage sag — the voltage dip in volts produced by the load-current step across that source impedance.
- Estimated sag — the dip expressed as a percentage of system voltage.
- Remaining voltage — the voltage remaining during the step, in volts and as a percent of system voltage.
Formula and Calculation Logic
For a three-phase, line-to-line voltage basis, the calculator derives source impedance from the fault current, then applies the load step to that impedance:
\(\displaystyle \text{Estimated source impedance: } Z = \frac{V_{system}}{\sqrt{3} \times I_{fault}}\)
\(\displaystyle \text{Estimated voltage sag: } V_{sag} = \sqrt{3} \times I_{step} \times Z\)
\(\displaystyle \text{Estimated sag (\%)} = \frac{V_{sag}}{V_{system}} \times 100\)
\(\displaystyle \text{Remaining voltage: } V_{remaining} = V_{system} - V_{sag}\)
The single-phase form drops the √3 term and applies \(Z = V_{system} / I_{fault}\) and \(V_{sag} = I_{step} \times Z\) directly. In both cases, the calculator treats fault current as a proxy for source strength rather than measuring true Thevenin impedance, phase angle, or X/R ratio.
Calculation Example
With system voltage 480 V, available fault current 10,000 A, load-current step 800 A, and phase count Three-phase:
- Estimated source impedance: (480 / (sqrt{3} times 10{,}000) = 480 / 17{,}320.5 = 0.0277 Omega)
- Estimated voltage sag: (sqrt{3} times 800 times 0.0277 = 38.4 text{V})
- Estimated sag: (38.4 / 480 times 100 = 8%)
- Remaining voltage: (480 – 38.4 = 441.6 text{V}), or 92% of system voltage
An 8% sag should be compared with the actual equipment undervoltage and ride-through thresholds; the calculator does not determine whether flicker, dropout, or nuisance tripping will occur.
Where This Result Is Used
The sag percentage and remaining voltage feed directly into equipment-tolerance review: contactor and PLC undervoltage settings, VFD ride-through settings, and lighting flicker complaints tied to motor or compressor starting. A calculated 8% sag against a load with a documented 10% dropout threshold indicates the load will hold through the start; a load rated for only 5% dropout will not. The same source-impedance figure is a starting point for reviewing available fault current at a panel, transformer sizing adequacy, and whether a soft starter, VFD, or reduced-voltage starting method is justified to limit the current step rather than accept the sag.
Field and Application Limits
Available fault current entered here is a scalar screening value, not a full short-circuit study result with X/R ratio, motor contribution, or utility source impedance breakdown. System voltage must match the actual line-to-line basis at the point being evaluated; mixing a line-to-neutral value into a three-phase calculation misstates the impedance and sag by a factor of √3. The calculator does not account for transformer impedance separately from the fault-current-derived impedance, does not model harmonic content, and does not apply any NEC article or utility power-quality standard—those checks (equipment undervoltage ratings, utility flicker limits, IEEE 519/1159 references where applicable) are separate engineering and utility-coordination steps that must be verified against actual field measurements, a certified short-circuit study, or the serving utility’s requirements before treating an 8% or any other calculated sag figure as accepted for a given installation.
FAQs
Is available fault current the same as source impedance?
No. The calculator uses available fault current as a convenient source-strength proxy. Use actual utility, transformer, and feeder impedance data for engineering studies.
Can this model motor starting accurately?
No. It screens a current step. Motor starting studies need motor, starter, transformer, feeder, and load-torque details.
What if the load-current step is higher than available fault current?
That is outside this simple screening model, so the calculator rejects it instead of reporting a nonphysical remaining-voltage result.