Watts Amps Volts Calculator
Estimate watts, volts, amps, and apparent power from real power, voltage, phase model, and power factor.
- Current estimate
- A
- Apparent power
- VA
- Apparent power
- kVA
- Phase multiplier
- x
- Power factor used
- PF
Calculation details
- Calculation basis
- Boundary
Recent results
Formulas
- \(S = \frac{P}{PF}\)
- \(k_{\mathrm{phase}} = 1\text{ for single-phase};\ \sqrt{3}\text{ for balanced three-phase}\)
- \(I = \frac{S}{V \times k_{\mathrm{phase}}}\)
Related tools: Ohm’s Law Calculator, Power Factor Calculator, and Electrical Load Calculator.
The Watts Amps Volts Calculator converts a known real power load into estimated current and apparent power. Enter real power, voltage, phase count, and power factor to estimate the amperes a load will draw and the VA or kVA that the electrical system must supply.
The current result is commonly used as a starting value when reviewing a branch circuit or feeder. It can support preliminary conductor sizing, AWG or kcmil selection, raceway fill planning, panel load review, voltage-drop calculations, and equipment load comparisons. For motors and other inductive loads, the power factor input prevents real watts from being treated as if they were equal to apparent power. For a multi-load schedule, continue with the Electrical Load Calculator.
The calculator performs load arithmetic for planning. Final conductor, overcurrent protective device, terminal, raceway, voltage-drop, equipment, and NEC compliance decisions require the actual installation details and the requirements enforced by the AHJ.
Electrical Inputs
| Input | Unit | Electrical use |
|---|---|---|
| Real power | W | The actual power consumed by the load. Enter the known load in watts. |
| Voltage | V | Use line-to-neutral voltage for single-phase line-neutral loads. Use line-to-line voltage for balanced three-phase loads. |
| Phase count | phase | Select Single-phase or the applicable balanced three-phase model for the current estimate. |
| Power factor | PF | Use 1.00 for a unity-power-factor load, or enter the measured or nameplate power factor. |
Real power, shown in watts, is the power that performs useful work or produces heat. Apparent power, shown in VA, represents the voltage-and-current demand placed on the supply. When power factor is below 1.00, the load requires more VA and more current than its wattage alone would suggest.
A resistive heater is often treated as unity power factor for preliminary arithmetic. A motor, transformer, driver, or other inductive load may have a lower nameplate or measured power factor, increasing calculated current for the same real-power value.
Current and Apparent Power
For a single-phase load, the calculator estimates current with:
\[I = \frac{P}{V \times PF}\]
Where:
- (I) = estimated current in amperes
- (P) = real power in watts
- (V) = voltage in volts
- (PF) = power factor
For a balanced three-phase load, the current relationship uses the three-phase multiplier:
\[I = \frac{P}{\sqrt{3} \times V \times PF}\]
The displayed phase multiplier identifies the phase relationship used by the calculation:
| Phase count | Phase multiplier |
|---|---|
| Single-phase | \(1\) |
| Balanced three-phase | \(\sqrt{3}\) |
Apparent power is calculated from real power and power factor:
\[S = \frac{P}{PF}\]
Where (S) is apparent power in volt-amperes. The calculator reports this value in both VA and kVA:
\[kVA = \frac{VA}{1000}\]
Calculation Example
Enter the following values:
| Field | Entered value |
|---|---|
| Real power | 1500 W |
| Voltage | 120 V |
| Phase count | Single-phase |
| Power factor | 1.00 |
For the single-phase current estimate:
\(\displaystyle I = \frac{1500}{120 \times 1.00} = 12.5\text{ A}\)
For apparent power:
\(\displaystyle S = \frac{1500}{1.00} = 1500\text{ VA}\)
\(\displaystyle 1500\text{ VA} \div 1000 = 1.5\text{ kVA}\)
The calculated results are:
- Current estimate: 12.5 A
- Apparent power: 1500 VA
- Apparent power: 1.5 kVA
- Phase multiplier: 1×
A 1,500 W, 120 V unity-power-factor single-phase load therefore produces an estimated line current of 12.5 A. That value can be carried into a preliminary branch-circuit ampacity review or used as the load current for an initial voltage-drop calculation.
Using the Result in Electrical Work
The current result establishes the electrical load value that must be compared with the rest of the installation.
For a branch circuit or feeder, the calculated current may be evaluated against conductor ampacity after considering the actual conductor material, AWG or kcmil size, insulation temperature rating, terminal rating, correction factor, adjustment factor, and number of current-carrying conductors. Raceway fill is a separate physical calculation based on the actual conductors and raceway selected.
For voltage-drop review, use the estimated current with the actual conductor length, conductor material, conductor size, and circuit arrangement. The calculator does not determine voltage drop because it does not include conductor length or impedance.
For balanced three-phase equipment, use the line-to-line voltage and the three-phase phase count. Applying a single-phase formula to a three-phase load, or using line-to-neutral voltage where line-to-line voltage is required, produces a current value that does not represent the intended system connection.
Field Verification
Use the load’s nameplate, manufacturer documentation, or measured electrical data when available. A nameplate ampere rating, motor data, equipment listing, duty cycle, continuous-load treatment, and installed terminal conditions can control the final design decision more directly than a watts-to-amps conversion.
The result assumes the entered real power, voltage, phase model, and power factor accurately represent the load. It does not account for unbalanced three-phase loading, starting current, harmonic current, non-linear load behavior, conductor derating, ambient temperature, terminal limitations, protective-device selection, or local AHJ requirements.
FAQs
Why does power factor change the current?
Power factor changes the apparent power needed to deliver the entered real power. Lower power factor means more current for the same watts.
What voltage should I use for three-phase?
Use line-to-line voltage for a balanced three-phase current estimate. Confirm the actual system and load connection before using the result.
Does this choose conductor size?
No. It estimates current from entered power assumptions only. Conductor and protection decisions need separate code, equipment, and job-condition review.